r2 - 12 Sep 2006 - 01:39:09 - KrishnanChitturYou are here: TWiki >  ChECourses Web  > ChE460 > PartialSolutionProblem14Set1
The rate expression is $V = \frac{V_{max}S}{K_m + S}$ where $V_{max}$ is the maximal reaction rate, $K_m$ is the Michaelis Menten constant and $S$ is the substrate concentration. The Lineweaver Burke plot can be used to determine both $V_{max}$ and $K_m$ - A plot of $\frac{1}{V}$ versus $\frac{1}{S}$, will have a slope that is equal to $\frac{K_m}{V_{max}}$ and a y-intercept of $K_m$

Consider this dataset which is the data from problem set 1, problem 14, Fall 2006. Here is how you can generate the plots using gnuplot

set1prob14plot.png

I then fit the two data sets to a straight line and plotted them on the same graph (I have not been able to include the gnuplot file here, but you can see the resulting image)

(The gnuplot command are listed here ... ) (do you know that you can upload your own file and generate plots like this if you want?)

The file used is set1prob14.dat (column 1 has the substrate concentration, column two for enzyme without inhibitor and column three with the inhibitor)

  • f(x)=m1*x+b1
  • g(x)=m2*x+b2
  • fit f(x) "set1prob14.dat" using (1.0/$1):(1.0/$2) via m1,b1
  • fit g(x) "set1prob14.dat" using (1.0/$1):(1.0/$3) via m2,b2
  • set terminal png
  • set output 'set1prob14.png'
  • plot 'set1prob14.dat' using (1.0/$1):(1.0/$2), 'set1prob14.dat' using (1.0/$1):(1.0/$3), f(x), g(x)

Here is what you get after fitting - look at the difference in slopes, similar intercept

-- KrishnanChittur - 06 Sep 2006

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elsedat set1prob14.dat manage 0.1 K 06 Sep 2006 - 13:47 KrishnanChittur  
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elsegnu set1prob14plot.gnu manage 0.3 K 06 Sep 2006 - 13:49 UnknownUser  
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